(a) (6, 3)
(b) (3, 6)
(b) (3, 6)
(c) (5, 6)
(d) (1, 4)
(a) (6, 3)
Explanation:

ABCD is a parallelogram, diagonals AC and BD bisect each other,
∴ mid point of AC= mid point of BD
= `"x + 1"/2` , `"6 + 2"/2` = `"3 + 4"/2` , `"5 + y"/2`
Now,
Comparing the co-ordinates,
= `"x + 1"/2` = `"3 + 4"/2`
= `"x + 1"/2` = `"7"/2`
= (1 + x) = 7
= x = (7-1)
= x = 6
Similarly,
= `"6 + 2"/2` = `"5 + y"/2`
= 4 = `"5 + y"/2`
= 4 x 2 = 5 + y
= 8 = 5 + y
= y = 8 - 5
= y = 3
∴ (x,y) = (6,3)
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