Find the Sum of First 51 terms of an AP Whose Secound and Third terms are 14 and 18 Respectively | Bzziii.com

Find the sum of first 51 terms of an AP whose secound and third terms are 14 and 18 respectively.







We Know that

`"a"_n` = a + (n - 1) d


Given 2nd term is 14

`"a"_2` = a + (2 - 1) d

14 = a + d

14 - d = a

a = 14 - d .....(1)
Given 3rd term is 18

`"a"_3` = a + (3 - 1) d

18 = a + d

18 - d = a

a = 18 - d .....(2)

From (1) & (2)

14 - d = 18 - 2d

2d - d = 18 - 14

d = 4

Putting value of d in (1)

a = 14 - d

a = 14 - 4

a = 10


Now, we need to find sum of first 51 terms

According formula,

`"S"_n` = `n/2` [2a + (n - 1) d]

Now, Putting values, (n = 51, a = 10 & d = 4 )

`"S"_n` = `51/2` [2`\times`10 + (51 - 1) 4]

`"S"_n` = `51/2` [20 + 50`\times`4]

`"S"_n` = `51/2` [20 + 200]

`"S"_n` = `51/2` `\times` 220

`"S"_n` = 51 `\times` 110

`"S"_n` = 5610

Hence, the sum of first 51 terms is 5610



Comments

Popular posts from this blog

Explain the Role of ‘Justice Party’ in Boycotting of Council Elections | bzziii.com

Who do you think is the ‘well-dressed customer’ at the shop?

A Trading Firm’s Average Inventory Is Rs 20,000 (Cost). If The Inventory Turnover Ratio Is 8 Times And The Firm Sells Goods At A Profit Of 20% On Sale, Ascertain the Profit of the firm.