If sec 4A=cosec (A - `20^0`), find the Value of A. (4A is an acute angle)
Given that, sec 4A = cosec (A - `20^0`) ….(i)
sec A = cosec (`90^0` - A)
By using property in equation (i) we get:
cosec (`90^0` - 4A) = cosec (A - `20^0`)
`90^0` - 4A = A - `20^0`
5A = `110^0`
A = `110^0/5`
A = `22^0`
sec A = cosec (`90^0` - A)
By using property in equation (i) we get:
cosec (`90^0` - 4A) = cosec (A - `20^0`)
`90^0` - 4A = A - `20^0`
5A = `110^0`
A = `110^0/5`
A = `22^0`
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