The Product of the Zeroes of 3x2 + 11x-2 is: (a) 2/3 (b) - 2/3 (c) 11/3 (d) -11/3

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The products of the zeroes of `3x^{2}+11x-2` is:

(a) `2/3`
(b) `-\frac{2}{3}`
(c) `11/3`
(d) `-\frac{11}{3}`




(a) `2/3`



Option (a) 2/3 is the correct answer.

⇒`3x^{2}+11x-2`

⇒`3x^{2}+11x-2` = 0

Here,

a = 3, b = 11 and c = -2

The Product of Zeroes = `"c"/"a"`

⇒`"c"/"a"`

⇒`-2/3`

The product of the zeroes of `3x^2` + 11x - 2 is: `-2/3`

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