The 26th term of the AP 0,-4,-8,-12..... is - (a) -96 (b) -100 (c) -104 (d) -108
The `26^"th"` term of the AP 0,-4,-8,-12..... is
(a) -96
(b) -100
(c) -104
(d) -108
(a) -96
(b) -100
(c) -104
(d) -108
(b) -100
Option (b) -100 is the correct answer.
⇒AP 0,-4,-8,-12..
Here,
a = 0
d = -8 - (-4)
= -8 + 4
= -4
n = 26
`a_26` = ?
d = -8 - (-4)
= -8 + 4
= -4
n = 26
`a_26` = ?
∴`a_n` = a + (n-1) d
⇒ `a_26` = 0 + (26-1)`\times`(-4)
= 0 + (25) `\times`(-4)
= 25`\times`-4
= -100
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