The 26th term of the AP 0,-4,-8,-12..... is - (a) -96 (b) -100 (c) -104 (d) -108

The `26^"th"` term of the AP 0,-4,-8,-12..... is

(a) -96
(b) -100
(c) -104
(d) -108

(b) -100

Option (b) -100 is the correct answer.

⇒AP 0,-4,-8,-12..

Here,

a = 0
d = -8 - (-4)
   = -8 + 4
   = -4
n = 26
`a_26` = ?

∴`a_n` = a + (n-1) d

⇒ `a_26` = 0 + (26-1)`\times`(-4)

               = 0 + (25) `\times`(-4)

               = 25`\times`-4

               = -100

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Class-10 SEBA
Maths Question Paper Solution 2022