You burn 6 grams of carbon in plenty of air: C ( s) + O2 ( g) = CO2 ( g)

You burn 6 grams of carbon in plenty of air:

C ( s) + O2 ( g) = CO2 ( g)

(a) What volume of gas will form (at rtp)?
(b) What volume of oxygen will be used up?

Solution for Question a) Given, mass = 6g

Ar = 12

Mr = 12g/mol

n = `"m"/"Mr"`

n = `"6g"/"12g"` mol

n = 0.5 mol

V = n `\times` Vm = 0.5mol `\times` 24dm`"cubed"/"mol"`

= 12dm (cubed)