An Antifreeze solution is made by mixing ethylene glycol (density= 1116 kg/m^3) with water. suppose that the specific gravity of such a solution is 1.0730. assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution?
Let x be the volume fraction of ethylene glycol.
Then 1-x is the volume fraction of water.
= (1-x)`\times`(1000) + x`\times`1116 = 1.0730`\times`1000 kg/`"m"^3`
= x(116) = 73
= x = 63%
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