Two cubes each of volume 64 `"cm"^3` are joined end to end. Find the surface area of the resulting cuboid.
48 `"cm"^2`
64 `"cm"^2`
80 `"cm"^2`
160 `"cm"^2`
48 `"cm"^2`
64 `"cm"^2`
80 `"cm"^2`
160 `"cm"^2`
160 `"cm"^2`
Option (d) 160 `"cm"^2` is the correct answer
It is Given that
Volume of 1 cube = 64 `"cm"^3`
`"(side)"^3` = 64 `"cm"^3`
`"a"^3` = 64 `"cm"^3`
`"a"^3` = 4`^3`
a = 4
So, a = 4 cm
Surface area of cuboid
Length of cuboid = a + a = 4cm + 4cm = 8cm
Breadth = a = 4cm
Height = a = 4cm
Area of cuboid = 2 (lb + bh + hl)
= 2 (8`\times`4 + 4`\times`4 + 4`\times`8)
= 2 (32 + 16 + 32)
= 2 (80)
= 160
Hence, Area of cuboid = 160 `"cm^2`
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