SOLVE 3x^2-2 root 6x+2 = 0 | Bzziii.com

Solve

`3x^2-2 \sqrt{6}x+2 = 0`

 `3x^2-2 \sqrt{6}x+2 = 0`

`3x^2-\sqrt{6}x-\sqrt{6}x+2=0`

`3x^2-\sqrt{2\times3}x-\sqrt{2\times3}x+2=0`

`3x^2-(\sqrt{2})(\sqrt{3})x-(\sqrt{2})(\sqrt{3})x+2=0`

`\sqrt{3}x(\sqrt{3}x-\sqrt{2})-\sqrt{2}(\sqrt{3}x-\sqrt{2})`=0

`(\sqrt{3}x-\sqrt{2})(\sqrt{3}x-\sqrt{2})`=0

`\sqrt{2}=0` `\sqrt{3}x=\sqrt{2}` `x=\frac{\sqrt{2}}{\sqrt{3}}` `x=\sqrt{\frac{2}{3}}`

`\sqrt{2}=0` `\sqrt{3}x=\sqrt{2}` `x=\frac{\sqrt{2}}{\sqrt{3}}` `x=\sqrt{\frac{2}{3}}`

Hence, x=`\sqrt{\frac{2}{3}}`  and `x=\sqrt{\frac{2}{3}}` are root of the equation

23 24 25 26 27

Class-10 SEBA
Maths Question Paper Solution 2022