The Median of the Following Data is 525. Find the Values of x and y, If the Total Frequency is 100. | Bzziii

The median of the following data is 525. Find the values of `x` and `y`, if the total frequency is 100.

Class interval0-100100-200200-300300-400400-500500-600600-700700-800800-900900-1000
Frequency25x121720y974




Median = 525

Median Class = 500 – 600

Class intervalFrequency (f)Cumulative frequency (cf)
0-10022
100-20057
200-300x7 + x
300-4001219 + x
400-5001736 + x
500-6002056 + x
600-700y56 + x + y
700-800965 + x + y
800-900772 + x + y
900-1000476 + x + y
N = `\sum` fi = 100 



= 76 + x + y = 100

= x + y = 24 ….(i)

Median = `1+\frac{\frac{n}{2}-F}{f}\times h`

Since, l=500,h=100,f=20,F=36+x and N=100

Therefore, putting the value in the Median formula, we get;

x = 9

y = 24 – x (from eq.i)

y = 24 – 9 = 15

Therefore, the value of x = 9 and y = 15.



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