FIND the Cordinates of the Point which Divides the Line Segment Joining the Points (4, -3) and (8, 5) in the Ratio 3:1 Internally. | Bzziii.com

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Find the cordinates of the point which divides the line segment joining the points (4, -3) and (8, 5) in the ratio 3:1 internally.









Let P(x,y) be the point which divides the line segment internally. Using the section formula for the internal division, i.e.
Find the cordinates of the point which divides the line segment joining the points (4, -3) and (8, 5) in the ratio 3:1 internally.


(x, y) = `(\frac{"m"_{1}"x"_{2}+"m"_{2}"x"_{1}}{"m"_{1}+"m"_{2}},\frac{"m"_{1}"y"_{2}+"m"_{2}"y"_{1}}{"m"_{1}+"m"_{2}})`

Given Us,

`"m"_1` = 3, `"m"_2` = 1

(`"x"_1`​,`"y"_1`​) = (4, −3)

(`"x"_2`​,`"y"_2`​) = (8, 5)

Putting the above values in the above formula, we get :

x = `\frac{3(8)+1(4)}{3+1}`, y = `\frac{3(5)+1(-3)}{3+1}`

x = `\frac{24+4}{4}`, y = `\frac{15-3}{4}`

x = `\frac{28}{4}`, y = `\frac{12}{4}`

x = 7, y = 3

Hence, (7,3) is the point which divides the line segment internally.






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