The equivalent resistance
(i) 3 ohms
(ii) 5.5 ohms
(iii) 7.5 ohms
(iv) 9.5 ohms
(ii) 5.5 ohms
(iii) 7.5 ohms
(iv) 9.5 ohms
(iii) 7.5 ohms
3Ω & 6Ω are in parallel.
So,
=`"R"_{1}`=`\frac{3\times6}{3+6}`
=`\frac{18}{9}`
= 2Ω
Now, R1 and 8Ω in series
So,
Rep = `\frac{"R"_{2}\times30}{"R"_{2}+30}`
= `\frac{10\times30}{10+30}`
= `300/40` = `30/4`
= `15/2` = 7.5Ω
Rep = `\frac{"R"_{2}\times30}{"R"_{2}+30}`
= `\frac{10\times30}{10+30}`
= `300/40` = `30/4`
= `15/2` = 7.5Ω
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