If the potential difference V applied across a conductor is increased to 2V with its temperature kept constant, free electrons in a conductor
(i) remain the same
(ii) become half of its previous value
(iii) be double of its initial value
(iv) become zero.
(ii) become half of its previous value
(iii) be double of its initial value
(iv) become zero.
(iii) be double of its initial value
Explanation:
`"V"_{"d"}`=`\frac{"eE"}{"ml"}\bar{\tau}`
= `e\frac{"V"}{"ml"}\bar{\tau}`
If temperature is kept constant, relaxation time `\bar{t}`- will remain constant, and e, m are also constants.
`"V"_{"d"}"a V"`
`"V"_{"d"}"a 2V"`
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