The above lens has a focal length of 10 cm. The object of height 2 mm is placed at a distance of 5 cm from the pole. Find the height of the image.
A. 4 cm
B. 6.67 mm
C. 4 mm
D. 3.33 mm
C. 4 mm
Explanation:
Given,
= `"h"_{1}` = 2mm = 0.2cm
= u = -5cm
= `1/f` = `1/v` - `1/5`
= `1/v` = `1/10` - `1/5`
= `"1-2'/"10"` = `-1/10`
= v = -10cm
Now,
= m = `v/u` = `\frac{h_{2}}{h_{1}}`
= m = `"-10"/"-5"` = `\frac{h_{2}}{0.2}`
= `"h"_{2}` = 0.4 cm = 4mm

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