Once four friends Rahul, Arun, Ajay, and Vijay went for a picnic at a hill station. 'Due to peak season, they did not get a proper Hotel in the city. The weather was fine so they decided to make a conical tent at a park. They were carrying 200 sq.m cloth with them. They made the conical tent with a height of 8m and a diameter of 12m. The remaining cloth was used for the floor
1. What is the slant height of the tent?
2. How much cloth was used for the floor?
3. What was the volume of the tent?
4. What was the area of the floor?
5. What was the total surface area of the tent?
conical tent with height 8m and diameter 12m.
Given radius = `12/2` = 6 m
h = 8 m
slant height L = √6² + `8^2` = 10 m
slant height of the tent = 10 m
Lateral surface Area = πRL
= π ( 6) ( 10)
= 60π
= 60 `\times` 3.14
= 188.4 `"m"^2`
cloth used for the floor = 200 - 188.4 = 11.6 `m^2`
volume of the tent = (`1/3`)π`R^2`h
= (`1/3`)(3.14) `\times` `6^2` `\times` 8
= 301.44 `m^3`
area of the floor = π`R^2`
= 3.14 `(6)^2`
= 113.04 `m^2`
0 Comments