Kalibasib runs 12.0 m east and then 28.0 m in a direction 30.0 degrees east of north. How far is Kalibasib from the starting point?
= `x^2` = `12^2` + `26^2` - 2(12)(28)cos120°
= 144 + 676 - (-336)
= 1156
x = √1156 = 34
Thus, Kalibasib is 34m far from the starting point.
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