A pile of 108 identical books has a mass of 30 kg.
Find out the
(a)the mass of 150 books and
(b)the number of books that has a mass of 20 kg.
Solution for (a) the mass of 150 books
Let be x = weight of 150 books.
So,
= 108 books : 30 kg
= 150 books : x kg
we can thus rewrite this as
`"108"/"30"` = `"150"/"x"`
= 3.6 = `"150"/"x"`
x = `"150"/"3.6"`
x = `"41.67"` kg
Solution for (b)the number of books that has a mass of 20 kg
let be y = number of books that has weight of 20 kg.
= 108 books : 30 kg
= y books : 20 kg
thus,
`"108"/"30"` = `"y"/"20"`
= 3.6 = `"y"/"20"`
y = 3.6 `\times` 20
y = 72 books
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