A couple plans to have three children.
What is the probability that
(a) they have all boys?
(b) they have at least one girl?
Solution for Question (a)
There are `"2"^3` = 8 possible combinations for two genders for three children.
Solution for Question (b)
There are (GGG, GGB, BGG, GBG) = 4 combinations where at least two of the children are girls.
Thus, there is a `4/8` = `1/2` probability that there will be at least two girls in the family of three children.
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