When Julia is writing a first draft, there is 0.7 probability that there will be no spelling mistakes on a page. One day, Julia writes a first draft that is 4 pages long. Assuming that Julia is equally likely to have a spelling mistake on each of the 4 pages, what is the probability that she will have no spelling mistakes on at least one of them? Round your answer to the nearest hundredth. P(at least one without mistakes)=
Assume P(E) = getting mistakes on all 4 pages.
Recall that the probability of an event not happening = 1 - P(E).
So,
P(at least one without mistakes) =1 − P(mistakes on all 4)
= 1 - `(0.3)^4` = 1−`(0.3)^4`
= 1 − 0.0081
= 0.9919
P(at least one without mistakes) ≈ 0.99.
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