Water enters a horizontal pipe with a rectangular cross section at a speed of 1.00 m/s. The width of the pipe remains constant but the height decreases. 27.3 m

Water enters a horizontal pipe with a rectangular cross section at a speed of 1.00 m/s. The width of the pipe remains constant but the height decreases. 27.3 m from the entrance, the height is half of what it is at the entrance. If the water pressure at the entrance is 2921 Pa, what is the pressure 27.3 m downstream?

half the area is twice the speed

V1 = 1 m/s

V2 = 2 m/s

Bernoulli

(1/2) rho `"V1"^2`+P1 = (1/2) rho `"V2"^2`+P2

rho water =1000 `"kg"/"m"^3`

2921 Pa is very low by the way, like 1 atm = 100,000 Pa for example. Perhaps they mean gage pressure.

500 `(1)^2` + 2921 = 500 `(2)^2` + P2

2921 - P2 = 1500

P2 = 1421 Pa