A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is

A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is

(1) 4n
(2) n
(3) 2n
(4) 3n

Option C is the Correct answer.

Explanation:

Displacement equation of SHM of frequency 'n' x = Asin(ωt) = Asin(2πnt)

Now,

Potential energy U = `\frac{1}{2}"kx"^2 = \frac{1}{2}"kA"^2 Sin^2 ("2πnt")`

= `\frac{1}{2}"kA"^2 [\frac{1-"cos"(2\pi("2n")"t")}{2}]`

So frequency of potential energy = 2n

`\therefore` if A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is 2n.