Find the value of m so that the quadratic equation mx(x-3)+9=0 has two equal roots.
Given equation,
= mx(x-3) + 9=0
= `"mx"^2` - 3mx + 9 = 0
We know that,
b² - 4ac = 0
⇒ `(-"3m")^2` - 4(m)(9) = 0
⇒ 9`"m"^2` - 4(m)(9) = 0
⇒ `"m"^2` - 4m = 0
⇒ m(m - 4) = 0
⇒ m = 0 ; m = 4
rejecting m = 0, Therfor the Value of m = 4
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