A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 20.0 from the horizontal

A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of `20.0^o` from the horizontal with a velocity of 40.0 m/s. How far will it travel in the air?

First do vertical problem

Vi = 40 sin 20 = 13.7 meters / second upward

v = Vi - g t

so at top v = 0

t = Vi / g = about 13.7 / 9.81 = 1.4 seconds upward on this planet

time in air = 2 t = 2.8 seconds, because it has to fall

Now,

Do horizontal problem

d = U t

but what is U

U = 40 cos 20 = 37.6 m/s

and at last

d = 37.6 * 2.8 = 105 meters (out of the park)