The Zeroes Of the Polynomial R(T) = -12T² + (K-3)T +48 Are Negative of Each Other - Bzziii.com

The zeroes of the polynomial r(t) = -12t² + (k-3)t +48 are negative of each other. Then k is

(a) 3

(b) 0

(c) -1.5

(d) -3






(d) -3

Explanation:

Let α and β be the zeroes of the polynomial.

∴ α = x, β = -x

We Know That,

Sum of zeroes = `"-b"/a`

α + β = `"k - 3"/"12"` = 0

= k - 3 = 0

∴ k = -3






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