The Zeroes Of the Polynomial R(T) = -12T² + (K-3)T +48 Are Negative of Each Other - Bzziii.com
The zeroes of the polynomial r(t) = -12t² + (k-3)t +48 are negative of each other. Then k is
(a) 3
(b) 0
(c) -1.5
(d) -3
(d) -3
Explanation:
Let α and β be the zeroes of the polynomial.
∴ α = x, β = -x
We Know That,
Sum of zeroes = `"-b"/a`
α + β = `"k - 3"/"12"` = 0
= k - 3 = 0
∴ k = -3
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