The Point On X Axis Equidistant From I And E Is - Bzziii.com

The point on x axis equidistant from I and E is

(a) (1/2, 0)

(b) (0,-1/2)

(c) (-1/2,0)

(d) ( 0,1/2)



(a) (1/2, 0) 

Explanation:

= `\sqrt{x-(-1)^{2}+(1-0)^{2}}` = `\sqrt{(x-1)^{2}+(0-1)^{2}}`

= `\sqrt{(x-1)^{2}+1^{2} }` = `\sqrt{(x-2)^{2}+1^{2} }`

= `(x+1)^{2}+1^{2}=(x-2)^{2}+1^{2}`

= `(x+1)^{2} =(x-2)^{2} `

= `x^{2}+2.x.1+1^{2}=x^{2}-2.x.2+2^{2}`

= `x^{2}+2x+1^{2}=x^{2}-4x+4`

= 1 + 2x = 4 - 4x

= 4x + 2x = 4 - 1

= 6x = 3

x = `3/6`

x = `1/2`


∴ Required coordination = (x,0) (`1/2` , 0)






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