(a) 0
(b) 2
(c) 20
(d) `2^{20}`
(b) 2
Explanation:
tan α + cot α = 2
given,
α=45°
So, tan α = cot α = 1
= `tan^{20}a`+ `cot^{20}a`
= `1^{20}`+ `1^{20}`
= 1+1 = 2
If tan α + cot α = 2, then `tan^{20}a`+ `cot^{20}a`
If tan α + cot α = 2, then `tan^{20}a`+ `cot^{20}a` =
(a) 0
(b) 2
(c) 20
(d) `2^{20}`
![]()
(b) 2
Explanation:
tan α + cot α = 2
given,
α=45°
So, tan α = cot α = 1
= `tan^{20}a`+ `cot^{20}a`
= `1^{20}`+ `1^{20}`
= 1+1 = 2
![]()
(a) 0
(b) 2
(c) 20
(d) `2^{20}`
(b) 2
Explanation:
tan α + cot α = 2
given,
α=45°
So, tan α = cot α = 1
= `tan^{20}a`+ `cot^{20}a`
= `1^{20}`+ `1^{20}`
= 1+1 = 2
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