(a) 0ᵒ
(b) 90ᵒ
(c) 45ᵒ
(d) 30ᵒ
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(c) 45ᵒ
(d) 30ᵒ
(b) 90ᵒ
Explanation:
= 2`"sin"^{2}`β – `"cos"^{2}`β = 2
= `"-cos"^{2}`β = 2 - 2`"sin"^{2}`β
= `"-cos"^{2}`β = 2 (1 - `"sin"^{2}`β)
= `"-cos"^{2}`β = 2 `"cos"^{2}`β
= `"-cos"^{2}`β - 2 `"cos"^{2}`β = 0
= 3`"cos"^{2}`β = 0
= `"cos"^{2}`β = 0
= cosβ = 0
This is Possible if β = `90^{2}`
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