ABC is such that AB=3 cm, BC= 2cm, CA= 2.5 cm. If ∆ABC ~ ∆DEF and EF = 4cm, then Perimeter of ∆DEF

ABC is such that AB=3 cm, BC= 2cm, CA= 2.5 cm. If ∆ABC ~ ∆DEF and EF = 4cm, then Perimeter of ∆DEF - Bzziii.com

admin September 19, 2021

∆ABC is such that AB=3 cm, BC= 2cm, CA= 2.5 cm. If ∆ABC ~ ∆DEF and EF = 4cm, then perimeter of ∆DEF is

(a) 7.5 cm

(b) 15 cm

(d) 30 cm

(b) 15 cm

Explanation:

Given,

AB=3cm, BC=2cm and CA=2.5cm and EF=4cm

Also, △ABC∼△DEF

Thus,

DEAB=EFBC=DFAC

DE3=42=DF2.5

Hence,

DE=6cm and

DF=5cm

Perimeter of Δ DEF = DE+EF+EF

Perimeter of Δ DEF = (4+5+6) cm

Perimeter of Δ DEF = 15 cm

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