In the figure Given Below, AD=4cm,BD=3cm and CB=12 cm, then cotƟ Equals - Bzziii

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In the figure given below, AD=4cm,BD=3cm and CB=12 cm, then cotƟ equals

AD=4cm,BD=3cm and CB=12 cm
(a) 3/4 
(b) 5/12 
(c) 4/3 
(d) 12/5 




In the figure given below, AD=4cm,BD=3cm and CB=12 cm, then cotƟ equals
(d) `12/5`

Explanation:
 
First we need to find AB,

By Pythagoras theorem

`"AB"^{2}`=`"AD"^{2}`+`"BD"^{2}`

=`"AB"^{2}`=`"4"^{2}`+`"3"^{2}`

=`"AB"^{2}`= 16 + 9
=`"AB"^{2}`= 25

=`"AB"^{2}`= `"5"^{2}`

∴ AB = 5

Now,

tan θ = `"AB"/"BC"`

tan θ = `"5"/"12"`

So,

cot θ = `12/5`

So, the correct answer is option (d) 12/5





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